Double
定义一些静态常量
public static final double POSITIVE_INFINITY = 1.0 / 0.0;
public static final double NEGATIVE_INFINITY = -1.0 / 0.0;
public static final double NaN = 0.0d / 0.0;
public static final double MAX_VALUE = 0x1.fffffffffffffP+1023; // 1.7976931348623157e+308
public static final double MIN_NORMAL = 0x1.0p-1022; // 2.2250738585072014E-308
public static final double MIN_VALUE = 0x0.0000000000001P-1022; // 4.9e-324
public static final int MAX_EXPONENT = 1023;
public static final int MIN_EXPONENT = -1022;
public static final int SIZE = 64;
public static final int BYTES = SIZE / Byte.SIZE;
构造器创建Double对象
public Double(double value) {
this.value = value;
}
public Double(String s) throws NumberFormatException {
value = parseDouble(s);
}
public static double parseDouble(String s) throws NumberFormatException {
return FloatingDecimal.parseDouble(s);
}
-
valueOf 创建 Double 对象*
public static Double valueOf(String s) throws NumberFormatException {
return new Double(parseDouble(s));
}
public static Double valueOf(double d) {
return new Double(d);
}
转字符串
public String toString() {
return toString(value);
}
public static String toString(double d) {
return FloatingDecimal.toJavaFormatString(d);
}
public static String toHexString(double d) {
/*
* Modeled after the "a" conversion specifier in C99, section
* 7.19.6.1; however, the output of this method is more
* tightly specified.
*/
if (!isFinite(d) )
// For infinity and NaN, use the decimal output.
return Double.toString(d);
else {
// Initialized to maximum size of output.
StringBuilder answer = new StringBuilder(24);
if (Math.copySign(1.0, d) == -1.0) // value is negative,
answer.append("-"); // so append sign info
answer.append("0x");
d = Math.abs(d);
if(d == 0.0) {
answer.append("0.0p0");
} else {
boolean subnormal = (d < DoubleConsts.MIN_NORMAL);
// Isolate significand bits and OR in a high-order bit
// so that the string representation has a known
// length.
long signifBits = (Double.doubleToLongBits(d)
& DoubleConsts.SIGNIF_BIT_MASK) |
0x1000000000000000L;
// Subnormal values have a 0 implicit bit; normal
// values have a 1 implicit bit.
answer.append(subnormal ? "0." : "1.");
// Isolate the low-order 13 digits of the hex
// representation. If all the digits are zero,
// replace with a single 0; otherwise, remove all
// trailing zeros.
String signif = Long.toHexString(signifBits).substring(3,16);
answer.append(signif.equals("0000000000000") ? // 13 zeros
"0":
signif.replaceFirst("0{1,12}$", ""));
answer.append('p');
// If the value is subnormal, use the E_min exponent
// value for double; otherwise, extract and report d's
// exponent (the representation of a subnormal uses
// E_min -1).
answer.append(subnormal ?
DoubleConsts.MIN_EXPONENT:
Math.getExponent(d));
}
return answer.toString();
}
}
判断
public static boolean isNaN(double v) {
return (v != v);
}
public static boolean isInfinite(double v) {
return (v == POSITIVE_INFINITY) || (v == NEGATIVE_INFINITY);
}
public static boolean isFinite(double d) {
return Math.abs(d) <= DoubleConsts.MAX_VALUE;
}
继承 Number 类,数值之间转换
public byte byteValue() {
return (byte)value;
}
public short shortValue() {
return (short)value;
}
public int intValue() {
return (int)value;
}
public long longValue() {
return (long)value;
}
public float floatValue() {
return (float)value;
}
public double doubleValue() {
return value;
}
hashCode/equals/compare
public int hashCode() {
return Double.hashCode(value);
}
public static int hashCode(double value) {
long bits = doubleToLongBits(value);
return (int)(bits ^ (bits >>> 32));
}
public boolean equals(Object obj) {
return (obj instanceof Double)
&& (doubleToLongBits(((Double)obj).value) ==
doubleToLongBits(value));
}
public int compareTo(Double anotherDouble) {
return Double.compare(value, anotherDouble.value);
}
public static int compare(double d1, double d2) {
if (d1 < d2)
return -1; // Neither val is NaN, thisVal is smaller
if (d1 > d2)
return 1; // Neither val is NaN, thisVal is larger
// Cannot use doubleToRawLongBits because of possibility of NaNs.
long thisBits = Double.doubleToLongBits(d1);
long anotherBits = Double.doubleToLongBits(d2);
return (thisBits == anotherBits ? 0 : // Values are equal
(thisBits < anotherBits ? -1 : // (-0.0, 0.0) or (!NaN, NaN)
1)); // (0.0, -0.0) or (NaN, !NaN)
}
运算
public static double sum(double a, double b) {
return a + b;
}
public static double max(double a, double b) {
return Math.max(a, b);
}
public static double min(double a, double b) {
return Math.min(a, b);
}